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Integration of current density vector (J) on a surface
Posted 19 Mar 2020, 07:58 GMT-4 Electrical, General, Results & Visualization Version 5.3 0 Replies
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I have understanding problem with results of integration of current density vector (J) on a surface. The J vector have same norm and tang (mostly x direction) component as you can see on uploaded pictures.
When I integrate it on a surface (XY plane, with same z=0.53 mm), i have result for norm (z direction), which is approximatly 1 A, this is acceptable for this model. But in the same time, i have result for tangent (x, y direction). In case of y direction is approximatly 0 A, which is acceptable, but in x direction its not even close to 0 A.
I understand that J vector had x component, but have can i have not 0 A as a result of integration of current density vector on a surface wich is an XY plane (same z=0.53 mm, ergo x, y components are paralell with this surface)? Or do I missing something? If I am, than what is physical meaning behind that?
Thanks for every help, and sorry for my eng. :)
Hello Körmöczi Andor
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